Homework Help Thread--SPLIT

[Anoohilator]

Why not just use normal right-angled triangle trigonometry? SOH CAH TOA and all that jazz..

...Cause its half 11 and I'm too tired to use my brain lol

Haha that's fair enough Just don't waste time in the exam doing it!

[Shoyru_Lover]

I remember Soh Cah Toa. I wanted to sock a toe into my math's teacher.

[charlixsparkles]

I'm reading "Love and Hate in Jamestown" by David Price and we need to find a "message" in the book. You know, what Price is trying to say...? Only this is a nonfiction book and it's kind of hard for me Anyone got any tips on how to find messages in books? Thanks x

[Mongrel]

Look at the introduction and the conclusion of the book. There are usually hints to the message there, although sometimes they're subtle.
Think about major people and places and what they might represent. Recall the most important events of the book, and try to find an allegory for the story. It's nonfiction, but the author still chooses which events/people to highlight and which ones to push to the back.
This is all pretty basic stuff, but I hope it helps.

[Hunter Lupe]

The book undoubtedly has a plot. The plot is typically not the message - the message is rather the conclusions one can draw from plot, combined with narratory style of the author. Therefore, try the following: summarize the book - what happens, when, why, where, etc. Then take a step back, and look at what appears in your summary, noting anything unusual - then ask yourself "why would anyone tell me this?". The answer to that question is often the message in a piece of literature.

Having said that, sometimes the message is the story - typically when it's important to the author to tell you about a specific series of events (boring autobiographies suffer from this).

[benladesh]

Well im horrible at understanding Calc

Find derivative

1
-----------
(T^4 +1)^3

Here is what I did and I am wrong

(1)(T^4 +1)^3 - (1) 3(T^4 +1)^2
----------------------------------
(T^4 +1)^6


((T^4 +1)^2) ((3)(T^4 +1))
----------------------------
(T^4 +1)^6


(3)(T^4 +1)
------------
(T^4 +1)^4


3
-----------
(T^4 +1)^3

I know its wrong. Th answer is

12T^3
------------
(T^4 +1)^4

[Anoohilator]

Well I got -12T³/ (T^4 + 1)^4 so don't know where I went wrong but this is how I went about doing it.

Rearranged to get (T^4 + 1)^-3

then replaced T^4+1 with u so I was left with y = (u)^-3 and u = T^4 + 1

I know that dy/dT = dy/du * du/dT

dy/du = -3 u^-4
du/dT = 4T³

dy/DT = -12T³/u^4

get rid of the u so

-12T³/(T^4 + 1)^4

...but dunno where I went wrong and it looks like you guys have a different way of looking at it

[benladesh]

wow your way looks much easier. We are mixing the chain and quotient rule. Its just long and painful in my opinion.
I just redid it with a friends help..its
-12t^3/(t^4 +1)^4

so you were right. Thx for the help ^_^

[guineadan]

Whilst flicking through my homework planner, I see that I have maths due in on tuesday
I'm stuck on the last question (I thought it was going a bit too well xD). So, here it is ^^

Find the maximum and minimum points (if any) of the following graphs:
e) y= 3x^4 - 8x^3 + 6x^2 + 1

Therefore:

dy/dx = 12x^3 - 24x^2 + 12x , which simplifies to:
dy/dx = x^3 - 2x^2 + x

Is it even possible to factorise this to get values of x?
I've tried making the -2x^2 + x part into brackets:
(-2x-1)(x-1), then adding the x to make it cubic:
x(-2x-1)(x-1) - but that doesn't work because there's a silly little 2 in front of that x^2 :p To factorise the quadratic bit, you need a 2 there though =S I know how to use the (d^2y)/(dx^2) thing - I just need help on this first bit

Suggestions, anyone?

[Sakura]

2. What reasons might there be for the timing, rapidity, and direction of Muslim territorial expansion? What more do you need to know in order to gain an understanding of the expansion of Islam?

Reference Text: The Earth And Its Peoples, A Global History. Third Edition, AP Ed.

[Anoohilator]

What is the overall capacitance of two capacitors in parallel, C1 and C2?

------------

Whilst flicking through my homework planner, I see that I have maths due in on tuesday
I'm stuck on the last question (I thought it was going a bit too well xD). So, here it is ^^

Find the maximum and minimum points (if any) of the following graphs:
e) y= 3x^4 - 8x^3 + 6x^2 + 1

Therefore:

dy/dx = 12x^3 - 24x^2 + 12x , which simplifies to:
dy/dx = x^3 - 2x^2 + x

Is it even possible to factorise this to get values of x?
I've tried making the -2x^2 + x part into brackets:
(-2x-1)(x-1), then adding the x to make it cubic:
x(-2x-1)(x-1) - but that doesn't work because there's a silly little 2 in front of that x^2 :p To factorise the quadratic bit, you need a 2 there though =S I know how to use the (d^2y)/(dx^2) thing - I just need help on this first bit

Suggestions, anyone?

You take 12x out as opposed to just twelve so you're left with 12x(x²-2x+1).

Last edited by Anoohilator on Sun Oct 14, 2007 10:22 pm, edited 1 time in total.

[Byakuya San]

I feel REALLY stupid for asking this, but what part of speech would "in spite of" be? Just one, not many.

[Mongrel]

Parts of speech are for individual words--"in" and "of" are prepositions, and "spite" is a noun. As an phrase it could probably be considered an idiom because we don't use the word "spite" that way normally.

[Skynetmain]

What is the overall capacitance of two capacitors in parallel, C1 and C2?

1/Ctot = 1/C1 + 1/C2
Ctot = 1/(1/C1 + 1/C2) = C1*C2/(C1 + C2)

Or something like that. Electronics wasn't my strong suit, but I do know the E-field of a capacitor is q/(epsilon naught)

[Anoohilator]

What is the overall capacitance of two capacitors in parallel, C1 and C2?

1/Ctot = 1/C1 + 1/C2
Ctot = 1/(1/C1 + 1/C2) = C1*C2/(C1 + C2)

Or something like that. Electronics wasn't my strong suit, but I do know the E-field of a capacitor is q/(epsilon naught)

Cheers bubba